A mixture of `0.1 mol ` of `Na_(2)O` and `0.1 mol ` of `BaO` is dissolved in `1000 g` of `H_(2)O`. Calculate the vapour pressure of solution at `373 K`.

9 g of glucose ( mol wt = 180 ) is dissolved in 90 of H_(2) O . Relative .lowering of vapour pressure is ___.

The molar mass of an organic compound is 58 g/mol. 24 g of this is dissolved in 600 g water, calculate its boiling point when vapour pressure of water becomes 760 mm. K_b" of "H_2O" is 0.513 K kg mol"^(-1) .

A solution is prepared by dissolving 2.0 g of glucose and 4.0 g urea in 100 g of water at 298 K . Calculate the vapour pressure of the solution ,If the vapour pressure of pure water is 23.756 torr. (Molecular mass of urea = 60 and glucose = 180g mol^(-1) )

The vapour pressure of water at 23^(@)C is 19.8 mm of Hg 0.1 mol of glucose is dissolved in 178.2g of water. What is the vapour pressure (in mm Hg) of the resultant solution?

The vapour pressure of water at T(K) is 20 mm Hg. The following solutions are prepared at T(K): I. 6g of urea (mol.wt.=60) is dissolved in 178.2 g of water. II. 0.01 mole of glucose is dissolved in 179.82 g of water. III. 5.3 g of Na_2CO_3 (mol.wt. =106) is dissloved in 179.1 g of water. Identify the correct order in which the vapour pressures of solutions increase:

The vapour pressure of water at T (K) is 20 mm Hg. The following solution are prepared at T (K) : I. 6g of urea (mol. Wt = 60) is dissolved in 178.2g of water II. 0.01 mole glucose is dissolved in 179.82 g of water III. 53g of Na_(2)CO_(3) (mo. wt. 106) is dissolved in 179.1g of water Identify the correct order in which the vapour pressures of solutions increases :