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" 19."3(x+6)+2(x+3)=64...

" 19."3(x+6)+2(x+3)=64

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Solve: 3(x+6)+2(x+3)=64 . Check the result.

Find x , if (2^(x - 1) . 2^(4x + 2))/2^(3x - 3) = 64

{(1/3)^(-3)-(1/2)^(-3)}-:(1/4)^(-3) = (a) (19)/(64) (b) (64)/(19) (c) (27)/(16) (d) (-19)/(64)

{(1/3)^(-3)-(1/2)^(-3)}-:(1/4)^(-3) = (19)/(64) (b) (64)/(19) (27)/(16) (d) (-19)/(64)

Show that (x + 4), (x - 3) and (x-7) are factors of x^3-6x^2 - 19x + 84 .

If (16)^(2x+3)=(64)^(x+3), then 4^(2x-2)=64(b)256(c)32(d)512

If (16)^(2x+3)=(64)^(x+3), then 4^(2x-2)= (a) 64 (b) 256 (c) 32 (d) 512

Evaluate lim_(x to 16) (x^(3//2) - 64)/(x - 16)

Evaluate lim_(x to 16) (x^(3//2) - 64)/(x - 16)

If 3^(x)=81 and 2^(x+y)=64 , then (x)/(y)=