[" 4) Each of two point charges are doubled and their "],[" distance is halved.Force of interaction becomes "n],[" times,where "n" is "],[" (a) "4],[" (b) "1],[" (c) "18],[" (d) "16]

Each of the two point charges are doubled and their distance is halved. Force of interaction becomes n times where n is

The mass of two bodies are doubled and the distance is halved, how will the gravitational force change?

[" Two charges of equal magnitude "],[" and at a distance 'r' exert a force 'F' "],[" on each other.If one of the charges "],[" doubled and distance between them "],[" is halved,the new force acting on "],[" each charge is "],[[" (A) "(F)/(8)],[" (B) "(F)/(4)],[" (C) ",8F],[" (D) "(F)/(16)]]

" The distance between two point charges is increased by "10%" .The force of interaction approximately "

When distance between two given magnetic poles is halved, force between them becoems k times, where k=

Charge on a capacitor is doubled. Its capacity becomes k times, where

Three capacitors of capacity C each are joined first in series and then in parallel. The capacity becomes n times where n is—

If the distance between two particles is halved, the gravitional force becomes

When the distance between two charged particles is halved, the force between them becomes four times.