If the speed of photoelectrons is `10^(4) ms^(-1)`, what should be the frequency of incident radiation on the potassium metal ? Work function of potassium = 2.3 eV.

If the speed of photoelectrons is 10^(6) ms^(-1) , what should be the frequency of the incident radiation on the potassium metal ? (Work function of potassium = 2.3 eV).

if the speed of photoelectrons is 10^4 m/s, what should be the frequency of the incident radiation on a potassium metal ? Given : Work function of potassium =2.3 eV

if the speed of photoelectrons is 10^4 m/s, what should be the frequency of the incident radiation on a potassium metal ? Given : Work function of potassium =2.3 eV

What is the energy of emitted photoelectrons is light of frequency 10^(16) Hz is incident on a sodium target ? Work function of sodium is = 2.5 eV.

The work function of a metal is 3.4 eV. If the frequency of incident radiation is increased to twice, then the work function of the metal becomes.

The work function of a metal is 3.4 eV. If the frequency of incident radiation is increased to twice, then the work function of the metal becomes.

The threshold frequency of potassium is 3 xx 10^14 Hz . The work function is