What volume of `3M Na_(2)SO_(4)` must be added to 25mL of 1M `BaCl_(2)` to produce `5g BaSO_(4)`?

What volume of 5M Na_2SO_4 must be added to 25 mL of 1M BaCl_2 to produce 10 g of BaSO_4 ?

If law of conservation of mass holds good, 2.00 g of Na_(2)SO_(4) will react with 3.00 g of BaCl_(2) to produce BaSO_(4) equal to

What will you notice when Na_(2)SO_(4) is added to BaCl_(2) in a test tube?

500 mL of 0.250 M Na_(2)SO_(4) solution is treated with 15.00 g of BaCl_(2) . Moles of BaSO_(4) formed are

500mL of 0.25M Na_(2)SO_(4) solution is added to an aquesous solution is 15g of BaCl_(2) resulting in the formation of a white precipatate of insoluble BaSO_(4) . How many moles and how many grams of BaSO_(4) are formed.

Give reason why BaSO_(4) will precipitate out when equal volumes of 2xx10^(-3) M BaCl_(2) solution and 2xx10^(-4)M Na_(2)SO_(4) solution are mixed. Given that the solubility product of BaSO_(4) is 1xx10^(-10).

Give reason why BaSO_(4) will precipitate out when equal volumes of 2xx10^(-3) M BaCl_(2) solution and 2xx10^(-4)M Na_(2)SO_(4) solution are mixed. Given that the solubility product of BaSO_(4) is 1xx10^(-10).