The product of ampere turn and area of coil is

The product of nuber of turns,area of coil and current is

The mutual inductance of a pair of coils, each of N turns, is M henry. If a current of I ampere in one of the coils is brought to zero in t second, the emf induced per turn in the other coil, in volt, will be

A coil of 200 turns has a cross-sectional area 900 mm It carries a current of 2 ampere. The plane of the coil is perpendicular to the uniform magnetic field of 0.5T. Calculate : magnetic moment

A coil of 200 turns has a cross-sectional area 900 mm It carries a current of 2 ampere. The plane of the coil is perpendicular to the uniform magnetic field of 0.5T. Calculate : torque acting on the coil

A current of 2 ampere is passed in a coil of radius 0.5 m and number of turns 20.The magnetic moment of the coil is

The ratio of induced emf in a coil of 50 turns and area A oscillating at frequency 50Hz to that in a coil of 100 turns and same area oscillating at frequency 100Hz is:

If the input voltage of a transformer is 2500 volts and output current is 80 ampere . The ratio of number of turns in the primary coil to that in secondary coil is 20 : 1 . If efficiency of transformer is 100 % , then the voltage in secondary coil as :

If the input voltage of a transformer is 2500 volts and output current is 80 ampere . The ratio of number of turns in the primary coil to that in secondary coil is 20 : 1 . If efficiency of transformer is 100 % , then the voltage in secondary coil as :

The coil of moving coil galvanometer twists through 90^@ when a current of one micro ampere is passed through it. If the area of the coil is 10^(-4) m^2 and its has 100 turns ,calculate the magnetic field of the magnet of the galvanometer, [ Given C=10^(-8) Nm / degree ]