The Young's modulus of a wire of length 2m and area of cross section `1 mm^(2)` is `2 xx 10^(11) N//m^(2)`. The work done in increasing its length by 2mm is

The young's modulus of a wire of length 2m and area of cross section 1mm^2 is 2 xx 10^10 N/m^2 . What is the work done in increasing it's length by 2mm.

The length of a wire is 1.0 m and the area of cross-section is 1.0 xx 10^(-2) cm^(2) . If the work done for increase in length by 0.2 cm is 0.4 joule, then Young's modulus of the material of the wire is

Young's modulus of rubber is 10^(4) N//m^(2) and area of cross section is 2 cm^(2) . If force of 2 xx 10^(5) dyn is applied along its length, then its final length becomes

Young's modulus of rubber is 10^(4) N//m^(2) and area of cross section is 2 cm^(-2) . If force of 2 xx 10^(5) dyn is applied along its length, then its initial l becomes

A wire (Y=2xx10^(11)N//m has length 1m and area 1mm^(2) . The work required to increase its length by 2mm is

A 1 m long steel wire of cross-sectional area 1 mm^(2) is extended 1 mm. If Y = 2 xx 10^(11) Nm^(-2) , then the work done is

The length of a rod is 20 cm and area of cross-section 2 cm^(2) . The Young's modulus of the material of wire is 1.4 xx 10^(11) N//m^(2) . If the rod is compressed by 5 kg-wt along its length, then increase in the energy of the rod in joules will be

The length of a rod is 20 cm and area of cross-section 2 cm^(2) . The Young's modulus of the material of wire is 1.4 xx 10^(11) N//m^(2) . If the rod is compressed by 5 kg-wt along its length, then increase in the energy of the rod in joules will be

A 20 N stone is suspended from a wire and its length changes by 1% . If the Young's modulus of the material of wire is 2xx10^(11)N//m^(2) , then the area of cross-section of the wire is 2xx10^(11)N//m^(2) , then the area of cross-section of the wire will be

A wire of length 1m is stretched by a force of 10N. The area of cross-section of the wire is 2 × 10^(–6) m^(2) and Y is 2 xx 10^(11) N//m^(2) . Increase in length of the wire will be -