Silicon dissolves in excess of HF due to formation of

Zinc(II) ion on reaction with NaOH first give a white precipitate which dissolves in excess of NaOH due to the formation of :

Zinc(II) ion on reaction with NaOH first give a white precipitate which dissolves in excess of NaOH due to the formation of :

Solution of ZnS in dil HCl , when treated with NaOH solution , a white ppt. is formed which dissolves in excess of NaOH due to the formation of :

Zn^(+2) dissolves in excess of NaOH due to the formation of

If group IV the ppt of Zn(OH)_(2) dissolve in excess of NaOH due to the formation of

Silver chloride dissolves in excess ammonia due to the formation of a soluble compplex whose formula is