`KI+I_(2)+HNO_(3) to HIO_(3)+KIO_(3)+NO_(2)`
If 3 moles of KI and 2 moles of `I_(2)` are mixed with excess `HNO_(3)` then volume of `NO_(2)` gas evolved at NTP is:

2KI+I_(2)+22HNO_(3)rarr2HIO_(3)+2KIO_(3)+22NO_(2)+10H_(2)O If 3 mole of KI & 2 moles I_(2) are reacted with excess of HNO_(3) . Volume of NO_(2) gas evolved at NTP is : 2KI+I_(2)+22HNO_(3)rarr2HIO_(3)+2KIO_(3)+22NO_(2)+10H_(2)O

2KI+I_(2)+22HNO_(3)rarr2HIO_(3)+2KIO_(3)+22NO_(2)+10H_(2)O If 3 mole of KI & 2 moles I_(2) are reacted with excess of HNO_(3) . Volume of NO_(2) gas evolved at NTP is : 2KI+I_(2)+22HNO_(3)rarr2HIO_(3)+2KIO_(3)+22NO_(2)+10H_(2)O

2KI+I_2+22HHNO_3to2HIO_3+2KIO_3+22NO_2+10H_2O If 3 mole of KI and 2 moles I_2 are reacted with excess of HNO_3 .Volume of NO_2 gas evolved at STP is :

How many moles of NO_(2) are produced when mole of B reacts with HNO_(3) ?

How many moles of NO_(2) are produced when mole of 'B' react with HNO_(3) ?

How many moles of NO_(2) are produced when 1 mole of B reacts with HNO_(3) ?

By the reduction of HNO_(3) to NO_(2) the number of moles of electrons involved per mole of HNO_(3) is

4Zn +10HNO_(3) to 4Zn(NO_(3))_(2) +NH_(4)NO_(3)+3H_(2)O . In this reaction one mole of HNO_(3) is reduced by