If `x = a{costheta + log tan((theta)/(2))} andy = a sin theta,` then `(dy)/(dx)` is equal to

If x=a{costheta+logtan""(theta)/(2)}" and "y=asintheta, then (dy)/(dx) is equal to

If x=a{costheta+logtan""(theta)/(2)}" and "y=asintheta, then (dy)/(dx) is equal to

If x = a (cos x + log tan theta/2) and y = a sin theta then dy/dx is equal to

x = a(costheta + logtan(theta/2), y = asintheta, find dy/dx.

If x=a(cos theta+log tan((theta)/(2))) and y=a sin theta then find (dy)/(dx) at theta=(pi)/(3) and theta=(pi)/(4)

If x = a(cos theta + log tan(theta/2)), y = a sin theta find dy/dx at theta = pi/3

If x=a(costheta+logtan(theta/2)) and y=a sin theta," show that "(dy)/(dx)=tantheta

If x = a (cos theta + log tan(theta/2)) and y = a sin theta , find the value of (d^2y)/(dx^2) at theta = pi/4