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Let f : R to R be differentiable at c i...

Let `f : R to R` be differentiable at ` c in R and f(c ) = 0` . If g(x) = |f(x) |, then at x = c, g is

A

not differentiable

B

differentiable if `f'(c ) ne 0 `

C

not differentiable if ` f'(c ) = 0 `

D

differentiable if ` f'( c ) = 0 `

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The correct Answer is:
To determine whether the function \( g(x) = |f(x)| \) is differentiable at \( x = c \), given that \( f \) is differentiable at \( c \) and \( f(c) = 0 \), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Information**: - We know that \( f: \mathbb{R} \to \mathbb{R} \) is differentiable at \( c \). - We have \( f(c) = 0 \). - We need to analyze the function \( g(x) = |f(x)| \) at \( x = c \). 2. **Define the Derivative of \( g \)**: - The derivative of \( g \) at \( c \) is defined as: \[ g'(c) = \lim_{h \to 0} \frac{g(c+h) - g(c)}{h} \] - Since \( g(c) = |f(c)| = |0| = 0 \), we can rewrite this as: \[ g'(c) = \lim_{h \to 0} \frac{|f(c+h)| - 0}{h} = \lim_{h \to 0} \frac{|f(c+h)|}{h} \] 3. **Consider the Behavior of \( f \)**: - Since \( f \) is differentiable at \( c \), we can apply the definition of the derivative: \[ f'(c) = \lim_{h \to 0} \frac{f(c+h) - f(c)}{h} = \lim_{h \to 0} \frac{f(c+h)}{h} \] - This means that as \( h \) approaches \( 0 \), \( f(c+h) \) approaches \( f(c) = 0 \). 4. **Evaluate the Limit for \( g'(c) \)**: - We need to analyze \( |f(c+h)| \) as \( h \) approaches \( 0 \): - If \( f'(c) > 0 \), then \( f(c+h) \) will be positive for small \( h \), and thus \( |f(c+h)| = f(c+h) \). - If \( f'(c) < 0 \), then \( f(c+h) \) will be negative for small \( h \), and thus \( |f(c+h)| = -f(c+h) \). - If \( f'(c) = 0 \), then \( f(c+h) \) approaches \( 0 \) from both sides. 5. **Final Evaluation**: - If \( f'(c) \neq 0 \), then \( g'(c) \) will be equal to \( |f'(c)| \), and thus \( g \) is differentiable at \( c \). - If \( f'(c) = 0 \), we need to check the left-hand and right-hand derivatives: - Both left-hand and right-hand derivatives will equal \( 0 \), thus \( g'(c) \) exists and is equal to \( 0 \). ### Conclusion: - Therefore, we conclude that \( g(x) \) is differentiable at \( x = c \) if \( f'(c) = 0 \) and also if \( f'(c) \neq 0 \). Hence, the correct option is: - **Differentiable if \( f'(c) = 0 \)**.

To determine whether the function \( g(x) = |f(x)| \) is differentiable at \( x = c \), given that \( f \) is differentiable at \( c \) and \( f(c) = 0 \), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Information**: - We know that \( f: \mathbb{R} \to \mathbb{R} \) is differentiable at \( c \). - We have \( f(c) = 0 \). - We need to analyze the function \( g(x) = |f(x)| \) at \( x = c \). ...
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