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A point on the straight line, 3x+5y=15 w...

A point on the straight line, `3x+5y=15` which is equidistant from the coordinate axes will lie only in

A

`IV` quadrant

B

`I` quadrant

C

`I` and `II` quadrant

D

`I` , `II` and `IV` quadrant

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AI Generated Solution

To find a point on the straight line \(3x + 5y = 15\) that is equidistant from the coordinate axes, we need to identify the conditions for a point to be equidistant from the axes. ### Step-by-step Solution: 1. **Understanding Equidistance from Axes**: A point \((x, y)\) is equidistant from the x-axis and y-axis if the absolute values of its coordinates are equal. This can be expressed as: \[ |x| = |y| ...
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