In the shown diagram friction exits at each contact surface with coefficient `mu` and the blocks are at rest. Then :

A block of mass M is being pulley along horizontal surface .The coefficient of friction the block and the surface is mu If another block of mass M//2 is placed on the block and it is pulled is again pulled on the surface , the coefficient of friction the block and the surface will be

A block of mass M is being pulley along horizontal surface .The coefficient of friction the block and the surface is mu If another block of mass M//2 is placed on the block and it is pulled is again pulled on the surface , the coefficient of friction the block and the surface will be

A block P is pushed momentarily along a horizontal surface with an initial velocity u if mu is the coefficient of sliding friction betweeen p and the horizontal surface then calculate the time taken by the block to attain the state of rest

A metal block of mass m is placed on a smooth metallic plane in support with string as shown in diagram. If after long time due to corrosiom, the contact surface becomes rough with coefficient of friction mu , then friction force acting on the block will be :

In the fig. as shown mass of each block is same. The surface are rough with coefficient of friction mu . The block B moves with acceleration a . The frictional force on the block C is kxxmu ma . Calculate the value of K

A block of mass m is pushed momentarily along a horizontal surface with an initial velocity u. If mu_k is the coefficient of kinetic friction between the object and surface, find the time at which the block comes to rest.

Figure shows an irregular wedge of mass m placed on a smooth horizontal surface. Part BC is rough. If the coefficient of friction between the block and wedge is mu , and the block comes to rest with respect to wedge at a point E on the rough surface then BE will be