Calculate the resistivity of an n-type semicondutor from the following data:density of conductionelectorns `=8xx10^13cm^(-3)`,density of holes `=5xx10^12cm^(-3),`mobility of conduction electron `=2.3xx10^(4)cm^(2)V_(-1)s_(-1)`and mobility of holes`=100cm^(2)V_(-1)s_(-1 ).`

Calculate the resistivity of an n-type semiconductor from the following data:density of conduction electrons =8xx10^13cm^(-3) ,density of holes =5xx10^12cm^(-3), mobility of conduction electron =2.3xx10^(4)cm^(2)V_(-1)s_(-1) and mobility of holes =100cm^(2)V_(-1)s_(-1 ).

Calculate the resistivity of an n-type semiconductor from the following data:density of conduction electrons =8xx10^13cm^(-3) ,density of holes =5xx10^12cm^(-3), mobility of conduction electron =2.3xx10^(4)cm^(2)V_(-1)s_(-1) and mobility of holes =100cm^(2)V_(-1)s_(-1 ).

In a semiconductor, the concentration of electrons is 8xx10^13cm and that of holes is 5xx10^12cm^-3 . Is it p-type or n-type semiconductor?

The number density of electron is 7xx10^(12)m^(-3) and number density of hole is 7xx10^(12)m^(-3) . This semiconductor will be ….. Type.

The number density of electron is a semiconductor is 8xx10^(13) cm^(-3) and number density of hole is 5xx10^(12) cm^(-3) then, (1) Which type of this semiconductor is? (2) How much is resistivity of it? (Mobility of electron is 23000 cm^(2)V^(-1)s^(-1) and mobility of hole is 100 cm^(2)V^(-1)s^(-1) and e=1.6xx10^(-19)C )

A semiconductor is known to have an electron concentric of 8xx10^(13)//cm^(3) and hole concentration of 5xx10^(12)//cm^(3) . The semiconductor is

A semiconductor is known to have an electron concentration of 8 xx 10^13 cm^-3 and hole concentration of 5 xx 10^12 cm^-3 . The semiconductor is

A semiconductor has the electron concentration 0.45 xx 10^(12) m^(-3) and hole concentration 5 xx 10^(29) m^(-3) . Find its conductivity . Given electron mobility = 0.135 m^(2) V^(-1) s^(-1) and hole mobility = 0.048 m^(2) V^(-1) s^(-1) , e = 1.6 xx 10^(-19) C