The pair of lines `sqrt3x^(2)-4xy+sqrt3y^(2)=0` are rotated about the origin by `pi//6` in anticlockwise sense. The equation of the pair in the new position, is

If the pair of lines sqrt(3)x^2-4x y+sqrt(3)y^2=0 is rotated about the origin by pi/6 in the anticlockwise sense, then find the equation of the pair in the new position.

If the pair of lines sqrt(3)x^2-4x y+sqrt(3)y^2=0 is rotated about the origin by pi/6 in the anticlockwise sense, then find the equation of the pair in the new position.

If the pair of lines sqrt(3)x^2-4x y+sqrt(3)y^2=0 is rotated about the origin by pi/6 in the anticlockwise sense, then find the equation of the pair in the new position.

If the pair of lines sqrt(3)x^2-4x y+sqrt(3)y^2=0 is rotated about the origin by pi/6 in the anticlockwise sense, then find the equation of the pair in the new position.

If the pair of lines sqrt(3)x^2-4x y+sqrt(3)y^2=0 is rotated about the origin by pi/6 in the anticlockwise sense, then find the equation of the pair in the new position.

If the pair of lines sqrt(3)x^(2)-4xy+sqrt(3)y^(2)=0 is rotated about the origin by (pi)/(6) in the anticlockwise sense,then find the equation of the pair in the new position.

If the pair of lines sqrt(3)x^(2)-4xy+sqrt(3)y^(2)=0 is rotated about the origin by pi//6 in the anticlockwise sense , then find the equation of the pair of lines in the new position.

If the pair of lines a x^(2)+2 h x y+b y^(2)=0 is rotated about the origin through 90^(0) , then their equation in the new position is given by

If the pair of straight lines ax^(2)+2hxy+by^(2)=0 is rotated about the origin through 90^(0), then find the equations in the new position.