Calculate the semi angular width of the fifth bright fringe from the central fringe.

In Young's double slit experiment, the distance between two coherent sources is 1 mm and the distance between the slits and the screen is 1 m. If the 10th dark fringe is at a distance of 4.75 mm from the central bright fringe, calculate the distance of 5th bright fringe from the central bright fringe.

In the double-slit experiment, the distance of the second dark fringe from the central line are 3 mm . The distance of the fourth bright fringe from the central line is

In Young's double slit experiment, the phase difference between the light waves producing the third bright fringe from the central fringe will be ( lamda=6000 Å)

In Young's double slit experiment, the phase difference between the light waves reaching third bright fringe from the central fringe will be (lambda=6000Å)

Fringe width equal to 1 mm is observed in the interference pattern of biprism experiment. Then the distance of nearest bright fringe from the central bright fringe will be :

To increase the angular width of interference fringes

In Fraunhofer.s single slit diffraction experiment, how does semi-angular width e of the central bright fringe depend on slit width .a.?