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2gk block is kept on 1kg block as shown ...

`2gk` block is kept on `1kg` block as shown . The friction between `1kg` block and fixed surface is absent and the coefficient of friction between `2kg` block is `mu=0.1`. A constant horizontal force `F=4N` is applied on `1kg` block. If the work done by the friction on `1 kg` block in `2s` is `-X J`, then find `X`. Take `g=10m//s^(2)`.

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