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A liquid is flowing through a horizontal...

A liquid is flowing through a horizontal channel. The speed of flow `(v)` depends on height `(y)` from the floor as `v = v_(0)[2((y)/(h))-((y)/(h))^(2)]`. Where `h` is the height of liquid in the channel and `v_(0)` is the speed of the top layer. Coefficient of viscosity is `eta`. Then the shear stress that the liquid exerts on the floor is.
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