If three distinct normals are drawn from `(2k, 0)` to the parabola `y^2 = 4x` such that one of them is x-axis and other two are perpendicular, then `k =`

Three normals drawn from a point (h k) to parabola y^2 = 4ax

Three normals are drawn from (k,0) to the parabola y^(2)=8x one of the normal is the axis and the remaining normals are perpendicular to each other,then find the value of k.

Three normals are drawn from the point (a,0) to the parabola y^2=x . One normal is the X-axis . If other two normals are perpendicular to each other , then the value of 4a is

Three normals are drawn from the point (a,0) to the parabola y^2=x . One normal is the X-axis . If other two normals are perpendicular to each other , then the value of 4a is

Three normals are drawn from the point (a,0) to the parabola y^2=x . One normal is the X-axis . If other two normals are perpendicular to each other , then the value of 4a is

Three normals are drawn from the point (a,0) to the parabola y^2=x . One normal is the X-axis . If other two normals are perpendicular to each other , then the value of 4a is

The number of distinct normals that be drawn from (-2,1) to the parabola y^(2)-4x-2y-3=0 is:

If three normals are drawn from point (h,0) on parabola y^(2)=4ax, then h>2a and one of the normal is axis of the parabola and other two are equally inclined to the axis of the parabola.Prove it?