The distance of a point on the ellipse `x^2/6 + y^2/2 = 1` from the centre is 2. Find the eccentric angle of the point.

The distance of a point on the ellipse x^(2) + 3y^(2) = 6 from its centre is 2. Find the eccentric angle of the point.

The distance of point on the ellipse x^2 + 3y^2 = 6 from the centre is 2. Find the eccentric angle of the point in the first quadrant. Also find the equation of the tangent at the point.

The distance of point on the ellipse x^2 + 3y^2 = 6 from the centre is 2. Find the eccentric angle of the point in the first quadrant. Also find the equation of the tangent at the point.

The distance of a point on the ellipse (x^2)/6+(y^2)/2=1 from the center is 2. Then the eccentric angle of the point is

The distance of a point on the ellipse (x^2)/6+(y^2)/2=1 from the center is 2. Then the eccentric angle of the point is pi/4 (b) (3pi)/4 (c) (5pi)/6 (d) pi/6

The distance of a point on the ellipse (x^2)/6+(y^2)/2=1 from the center is 2. Then the eccentric angle of the point is pi/4 (b) (3pi)/4 (c) (5pi)/6 (d) pi/6

The distance of a point on the ellipse (x^2)/6+(y^2)/2=1 from the center is 2. Then the eccentric angle of the point is pi/4 (b) (3pi)/4 (c) (5pi)/6 (d) pi/6

The distance of a point on the ellipse x^(2)//6+y^(2)//2=1 from the centre is 2. The eccentric angle of the point is

If the distance of a point of the ellipse x^2/6+y^2/2=1 from the center is 2, then the eccentric angle is

The distance of a point on the ellipse (x^(2))/(6)+(y^(2))/(2)=1 from the centre is 2 Then the eccentric angle of the point is