If a simple pendulum is taken to place where g decreases by 2%, then the time period

If the percentage decrease in the length of a simple pendulum is 10%, then find the percentage decrease in its time period

The time period of simple pendulum is T. If its length is increased by 2%, the new time period becomes

If the length of a simple pendulum is increased by 2%, then the time period

If the length of a simple pendulum is increased by 2%, then the time period

Assertion : The length of a simple pendulum is increases by 4% the corresponding decrease in time period will be 2% Reason : T = prop sqrt(1)

The period of a simple pendulum is found to increases by 50% when the length the pendulum is increases by 0.6m. Calculate the initial length and the initial period of oscillation at a place where g=9.8 m//s^(2) .

If the length of a simple pendulum is decreased by 2%, find the percentage decrease in its period T, where T = 2pi sqrt((l)/(g))

If the length of a simple pendulum is decreased by 2%, find the percentage error in its period T.