Assertion : Velocity and acceleration of a particle are given as,
`v=hati-hatj and a=-2 hati+2 hatj` This is a two dimensional motion with constant acceleration.
Reason : Velocity and acceleration are two constant vectors.

Velocity and acceleration of a particle are v=(2 hati-4 hatj) m/s and a=(-2 hati+4 hatj) m/s^2 Which type of motion is this?

Velocity and acceleration of a particle are v=(2 hati-4 hatj) m/s and a=(-2 hati+4 hatj) m/s^2 Which type of motion is this?

Velocity and acceleration of a particle are v=(2 hati) m/s and a = (4t hati+t^2 hatj) m /s^2 where, t is the time. Which type of motion is this ?

Velocity and acceleration of a particle are v=(2 hati) m/s and a = (4t hati+t^2 hatj) m /s^2 where, t is the time. Which type of motion is this ?

The initial velocity and the acceleration of a particle are vecu=3hati+4hatj and veca=0.3 hati+0.4hatj . The magnitude of its velocity after 10 s is

Velocity and acceleration of a particle at time t=0 are u=(2 hati+3 hatj) m//s and a=(4 hati+3 hatj) m//s^2 respectively. Find the velocity and displacement if particle at t=2s.

Velocity and acceleration of a particle at time t=0 are u=(2 hati+3 hatj) m//s and a=(4 hati+3 hatj) m//s^2 respectively. Find the velocity and displacement if particle at t=2s.

For any particle moving with some velocity (vecv) & acceleration (veca) , tangential acceleration & normal acceleration are defined as follows. Tangential acceleration - The component of acceleration in the direction of velocity. Normal acceleration - The component of acceleration in the direction perpendicular to velocity. If at a given instant, velocity & acceleration of a particle are given by . vecc=4hati +3hatj veca=10hati+15hatj+20hatk Find the normal acceleration of the particles at the given instant :-

For any particle moving with some velocity (vecv) & acceleration (veca) , tangential acceleration & normal acceleration are defined as follows. Tangential acceleration - The component of acceleration in the direction of velocity. Normal acceleration - The component of acceleration in the direction perpendicular to velocity. If at a given instant, velocity & acceleration of a particle are given by . vecc=4hati +3hatj veca=10hati+15hatj+20hatk Find the tangential acceleration of the particle at the given instant :-