If the slope of the curve `y=(ax)/(b-x)` at the point (1, 1) is 2, then

One of the diameters of the circle circumscribing the rectangle ABCD is 4y=x+7 . If A and B are the points (-3, 4) and (5, 4) and slope of the curve y = (ax)/(b-x) at point (1, 1) be 2 , then centre of circle is : (A) (a, b) (B) (b, a) (C) (-a, -b ) (D) (a, -b)

Find the slope of the tangent to the curve y(x^2+1)=x at the point (1, 1/2)

Find the slope of tangent of the curve y =4x at the point (-1,4).

Find the slope of the tangent to the curve : y=x^(3)-2x+8 at the point (1, 7) .

The slope of the curve y = x^(3) - 2x+1 at point x = 1 is equal to :

The slope of tangent to the curve y=2tan^(-1)x at the point x=0 is

The slope of tangent to the curve y=2tan^(-1)x at the point x=0 is

At what points,the slope of the curve y=-x^(3)+3x^(2)+9x-27 at point (x,y) is given by maximum slope.

The slope of the curve 2y^(2)=ax^(2)+b at (1,-1) is -1 Find a,b