8 kg wheel has radius of gyration (1/4) m. The torque required to give it an angular acceleration of 4 `rad//s^(2)`, is

If a wheel has mass 70 kg and radius of gyration 1 m, then the torque required for an angular acceleration of 2 rev/s^2 will be

The moment of inertia of a body is 2.5 kg m^(2) . Calculate the torque required to produce an angular acceleration of 18 rad s^(-2) in the body.

If a wheel has mass 70 kg and radius of gyration 1 m, then the torque required an angular 1 m, then the torque required an angular acceleration of "2 rev"//s^(2) will be

A torque tau applied to a dise of mass 2 kg and radius of gyration 15 cm produces an angular acceleration of 5 "rad"//sec^(2) . Find the value of tau .

A torque of 10^(8) dyne - cm is applied to a fly wheel of mass 10 kg and radius of gyration 50 cm . What is the resultant angular acceleration ?

A torque of 10 Nm is applied to a flywheel of mass 10 kg and radius of gyration 50 cm. What is the resultant angular acceleration ?

A torque of 10 Nm is applied to a flywheel of mass 5 kg and radius of gyration 0.6 m. What is the resultant angular acceleration ?

A torque of 10 Nm is applied to a flywheel of mass 10 kg and radius of gyration 50 cm. What is the resulting angular acceleration ?

A wheel of radius 0.4m can rotate freely about its axis as shown in the figure. A string is wrapped over its rim and a mass of 4 kg is hung. An angular acceleration of 8 rad//s^(2) is produced in it due to the torque. Then, the moment of inertia of the wheel is ( g=10m//s^(2) )

A wheel of radius 0.4m can rotate freely about its axis as shown in the figure. A string is wrapped over its rim and a mass of 4 kg is hung. An angular acceleration of 8 rad//s^(2) is produced in it due to the torque. Then, the moment of inertia of the wheel is ( g=10m//s^(2) )