If the string of a conical pendulum makes an angle `theta` with horizontal, then square of its time period is proportional to

A conical pendulum of length L makes an angle theta with the vertical. The time period will be

A conical pendulum of length L makes an angle theta with the vertical. The time period will be

When the string of a conical pendulum makes an angle of 45^(@) with the vertical , its time is T_(1) when the string makes an angle of 60^(@) with the vertical , its time period is T_(2) then T_(1)^(2) // T_(2)^(2) is

When the string of a conical pendulum makes an angle of 45^(@) with the vertical , its time is T_(1) when the string makes an angle of 60^(@) with the vertical , its time period is T_(2) then T_(1)^(2) // T_(2)^(2) is

A simple pendulum is set up on a trolley which slides down a frictionless inclined plane making an angle theta with horizontal. The time period of pendulum is

A projectile is projected with a speed u at an angle theta with the horizontal. What is the speed when its direction of motion makes an angle theta//2 with the horizontal

A heavy & big sphere is hang with a string of length l. This sphere move in a horizontal circular path making an angle theta with vertical then its time period is

A heavy & big sphere is hang with a string of length l. This sphere move in a horizontal circular path making an angle theta with vertical then its time period is

A simple pendulum of length l is set in motion such that the bob, of mass m, moves along a horizontal circualar path , and the string makes a constant angle theta with the vertical. The time period of rotation of the bob is l and the tension in the thread is T