To divide a line segment AB in the ratio 4:7, a ray AX is drawn first such that `angleBAX` is an acute angle and then points `A_(1),A_(2),A_(3),…..` are located at equal distance on the ray AX and the point B is joined to

To divide a line segment AB in the ration 4:7 , a ray AX is first drawn such that BAX is an acute angle and then points A_1, A_2, A_3 , … located at equal distance on the ray AX and the point B is joined to

To divide segment AB in the ratio 3:5, ray AX is drawn such that angleBAX is an acute angle. Then, the number of points to be marked at equal distance on AX must be at least ....

To divide a line segment AB in the ratio 5:7, first a ray AX is drawn, so that /_BAX is an acute angle and then at equal distances point are marked on the ray AX such that the minimum number of these points is

To divide a line segment AB in the ratio 5 : 7 , first a ray AX is drawn so that BAX is an acute angle and then at equal distances points are marked on the ray AX such that the minimum number of these points is

To divide a line segment AB in the ratio 5:7, first a ray AX is drawn, so that /_BAX is an acute angle and then at equal distances point are marked on the ray AX such that the minimum number of these points is

To divide a line segment BC internally in the ratio 3 : 5, we draw a ray BX such that angle CBX is an acute angle. What will be the minimum number of points to be located at equal distances, on ray BX?

To divide a line segment AB in the ratio 5:6, draw a ray AX such that angleBAX is an acute angle, the draw a ray BY parallel to AX and the points A_(1),A_(2),A_(3),….." and " B_(1),B_(2),B_(3),….. are located to equal distances on ray AX and BY, respectively. Then, the points joined are

To divide a line segment AB in the ratio 5 : 6 , draw a ray AX such that BAX is an acute angle , drawn a ray BY parallel to AX with the points A_(1) , A_(2), A_(3), ,… and B_(1), B_(2), B_(3) ,… located at equal distances on ray AX and BY respectively. Then the points joined are