The reaction
`3Fe(s)+4H_(2)O hArr Fe_(3)O_(4)(s) +4H_(2)(g)` is reversible if it is carried out

Balance the equation , Fe + H_(2)O to Fe_(3)O_(4) + H_(2)

For the equilibrium reaction, 3Fe_((s)) + 4H_(2) O_((g)) hArr Fe_(3)O_(4(s)) + 4 H_(2(g)) the relation between K_(p) and K_(c) is

K_(rho) for the following reaction will be equal to 3Fe(s)+4H_(2)O(g)hArrFe_(3)O_(4)(s)+4H_(2)(g)

K_(rho) for the following reaction will be equal to 3Fe(s)+4H_(2)O(g)hArrFe_(3)O_(4)(s)+4H_(2)(g)

{:(List - I , List - II),((A)CaCO_(3) hArr CaO + CO_(3),(P) K_(p) = K_(c)),((B) NH_(4) HS hArr NH_(3)+ H_(2)S,(Q) "High pressure favours backward reaction"),((C) PCI_(5) hArr PCI_(3) + CI_(2),(R) K_(p) = K_(c) (RT)),((D) 3Fe(s) + 4H_(2) O(g) hArr Fe_(3) O_(4) (s) + 4H_(2)(g), (S) " Heterogeneous equilibrium "):}

{:(List - I , List - II),((A)CaCO_(3) hArr CaO + CO_(3),(P) K_(p) = K_(c)),((B) NH_(4) HS hArr NH_(3)+ H_(2)S,(Q) "High pressure favours backward reaction"),((C) PCI_(5) hArr PCI_(3) + CI_(2),(R) K_(p) = K_(c) (RT)),((D) 3Fe(s) + 4H_(2) O(g) hArr Fe_(3) O_(4) (s) + 4H_(2)(g), (S) " Heterogeneous equilibrium "):}

Write the expression for equilibrium constant K_(p) for the reaction, 3 Fe (s) + 4 H_(2)O (g) hArr Fe_(3)O_(4) (s) + 4 H_(2)(g).