For `0ltalphaltbetalt(pi)/(2),if(sinalpha)/(sinbeta)=(sqrt3)/(2)and (cosalpha)/(cosbeta)=(sqrt5)/(2),then`

If sinalpha+sinbeta=1//2 and cosalpha+cosbeta=sqrt(3)//2 then 3beta+alpha =

If (cosalpha)/(sinbeta)=n and (cosalpha)/(cosbeta)=m , then find cos^(2)beta ?

Let alphaandbeta be such that piltalpha-betalt3pi . If sinalpha+sinbeta=-(21)/(65)and cosalpha+cosbeta=-(27)/(65) , then the value of "cos"((alpha-beta))/(2) is

(cosalpha+cosbeta)^2+(sinalpha+sinbeta)^2 =

sinalpha+sinbeta=a ,cosalpha+cosbeta=b=>sin(alpha+beta)

If sinalpha+sinbeta=a ,cosalpha+cosbeta=b=>sin(alpha+beta) =

The expression (sinalpha+sinbeta)/(cosalpha+cosbeta) is equal to

If alpha+beta=(pi)/(2) , then prove that cosalpha=sqrt((sinalpha)/(cosbeta)-sinalphacosbeta)

Simplify (sinalpha+sinbeta)/(cosalpha-cosbeta)+(cosalpha+cosbeta)/(sinalpha-sinbeta)

Prove that: (cosalpha+cosbeta)^2+(sinalpha+sinbeta)^2=4cos^2((alpha-beta)/2)