An atomic nucleus `._90 Th^232` emits several `alpha` and `beta` radiations and finally reduces to `._82 Pb^208`. It must have emitted.

Thorium isotope ._(90)Th^(232) emits some alpha -particle and some beta -particle and gets transformed into lead isotope ._(82)Pb^(200) . Find the number of alpha -and beta -particles emitted.

90 Th^ 232 emits 'X' alpha particles and 'Y' beta particles in succession and is converted into "_82 Pb^ 200 , find 'X' and 'Y'.

._(90)Th^(232) emits 6alpha and 4 beta particles and gets converted into a lead. The mass number and atomic number of lead is

The Th_(90)^(232) atom has successive alpha and beta decays to the end product Pb_(82)^(208) . The numbers of alpha and beta. Particles. Emitted in the process respecitvely are-

A radioactive element X emits six alpha -particles and four beta -particles leading to end product ""_(82)^(208)Pb . X is

A radioactive element X emits six alpha -particles and four beta -particles leading to end product ""_(82)^(208)Pb . X is

Uranium nucleus ""_(92)^(238) U undergoes several disintegrations and ultimately decays to lead nucleus ""_(82)^(206) Pb . How many alpha and beta particles are emitted ?

92^(U^(238)) undergoes a series of changes by emitting alpha and beta particles and finally 82^(pb^(206)) is formed. Calculate the number of and particles emitted during the change.