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7(x-2)-4(5-x)=1...

`7(x-2)-4(5-x)=1`

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3(5x-2)-4(x+4)=7(x-1)+1

If 7^(log 7(x^(2)-4x + 5))=x - 1 , x may have values

If 7^(log 7(x^(2)-4x + 5))=x - 1 , x may have values

3((7x+1)/(5x-3))-4((5x-3)/(7x+1))=11;x!=(3)/(5),-(1)/(7)

Solve the quadratic equation by factorisation: 3((7x+1)/(5x-3))-4((5x-3)/(7x+1))=11 x != 3//5, x != 1//7

((x-2)(x-4)(x-7))/((x+2)(x+4)(x+7))>1