`sec72^(@) - sec 36^(@) = `

sec 72 ^(@) - sec 36^(@) = 2.

Write the values of sec 0^(@) ,sec 30^(@) , sec 45^(@) , sec 60^(@) and sec 90^(@) . What happens to sec x when x increases from 0^(@) "to "90^(@) ?

Write the values of sec0^(@), sec 30^(@), sec 45^(@), sec 60^(@) and sec 90^(@) . What happens to sec x when x increases from 0^(@) to 90^(@) ?

sec^(-1)[sec(-30^(@))] =

sec^(-1)[sec(-30^(@))] =

cos 36^(@) - cos 72^(@) =

The numerical value of cot 18^(@) (cot 72^(@) cos^(2) 22^(@) + (1)/(tan 72^(@) sec^(2) 68^(@))) is

The value of sec 40^(@)+sec 80^(@)+sec 160^(@) will be

The value of sec 40^(@)+sec 80^(@)+sec 160^(@) will be