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[[3,-1,3],[-1,0,2]][[2,-3],[1,0],[3,1]]...

`[[3,-1,3],[-1,0,2]][[2,-3],[1,0],[3,1]]`

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Show that [[1,2,3],[0,1,0],[1,1,0]] [[-1,1,0],[0,-1,1],[2,3,4]] ne [[-1,1,0],[0,-1,1],[2,3,4]][[1,2,3],[0,1,0],[1,1,0]]

Show that: [[1,2,3],[0,1,0],[1,1,0]][[-1,1,0],[0,-1,1],[2,3,4]] ne [[-1,1,0],[0,-1,1],[2,3,4]][[1,2,3],[0,1,0],[1,1,0]]

Evaluate the following : [[1,-1],[0,2],[2,3]]([[1,0,2],[2,0,1]]-[[0,1,3],[1,0,2]])

Evaluate the following : [[1,-1],[0,2],[2,3]]([[1,0,2],[2,0,1]]-[[0,1,3],[1,0,2]])

Find A such that [[2,3,4],[1,0,-2],[3,1,-1]]+A=[[1,2,-1],[2,-1,0],[1,3,2]]

If A=[[1,2,3],[2,0,-2]],B=[[1,1,-1],[2,0,3],[3,-1,2]] and C=[[1,3],[0,2],[-1,4]] find A(BC).

If A=[[1,0,-2],[2,3,-1]], B=[[4,-1,3],[0,2,1]]"and" C=[[2,-3,0],[1,4,5]] "find " A-3B+3C

" Let "A" be a "3times3" matrix such that "A[[1,2,3],[0,2,3],[0,1,1]]=[[0,0,1],[1,0,0],[0,1,0]]" .Then "A^(-1)" is "

Find A if [[1,0,-1],[-2,-1,4],[-1,0,2]]A = [[-1,-2,2],[3,4,-3],[3,4,-1]]

Evaluate : [[1,3,5]][[1,0,3],[2,0,1],[0,1,2]][[1],[4],[6]]