Two particles of a mass 2m and m are tied with an inextensible string the particle of mass m is given a speed V as shown in the figure. Find the speed with which the particle of mass 2m starts moving.

A particle of mass m_0 , travelling at speed v_0 . Strikes a stationary particle of mass 2m_0 . As a result of the particle of mass m_0 is deflected through 45^@ and has a final speed of v_0/sqrt2 . Then the speed of the particle of mass 2m_0 after this collision is

A particle of mass m_0 , travelling at speed v_0 . Strikes a stationary particle of mass 2m_0 . As a result of the particle of mass m_0 is deflected through 45^@ and has a final speed of v_0/sqrt2 . Then the speed of the particle of mass 2m_0 after this collision is

A particle of mass 2m moving with velocity v strikes a stationary particle of mass 3m and sticks to it . The speed of the system will be

A particle of mass 2m moving with velocity v strikes a stationary particle of mass 3m and sticks to it . The speed of the system will be

A particle of mass 2m moving with velocity v strikes a stationary particle of mass 3m and sticks to it. The speed of the system will be

Two particles each of mass m are connected by a light inextensible string and a particle of mass M is attached to the midpoint of the string. The system is at rest on a smooth horizontal table with string just taut and in a straight line. The particle M is given a velocity v along the table perpendicular to the string. Prove that when the two particles are about to collide : (i) The velocity of M is (Mv)/((M + 2m)) (ii) The speed of each of the other particles is ((sqrt2M (M + m))/((M + 2m)))v .

Two particles each of mass m are connected by a light inextensible string and a particle of mass M is attached to the midpoint of the string. The system is at rest on a smooth horizontal table with string just taut and in a straight line. The particle M is given a velocity v along the table perpendicular to the string. Prove that when the two particles are about to collide : (i) The velocity of M is (Mv)/((M + 2m)) (ii) The speed of each of the other particles is ((sqrt2M (M + m))/((M + 2m)))v .

Two particles each of mass m are connected by a light inextensible string and a particle of mass M is attached to the midpoint of the string. The system is at rest on a smooth horizontal table with string just taut and in a straight line. The particle M is given a velocity v along the table perpendicular to the string. Prove that when the two particles are about to collide : (i) The velocity of M is (Mv)/((M + 2m)) (ii) The speed of each of the other particles is ((sqrt2M (M + m))/((M + 2m)))v .

A particle of mass m moving towards west with speed v collides with another particle of mass m movies towards south. If two particles st ich t o each other the speed of the new particle of mass 2 m will be