In `Delta` ABC, P, Q, R are points on BC, CA and AB respectively, dividing them in the ratio 1 : 4, 3 : 2 and 3 : 7. The point S divides AB in the ratio 1 : 3. Then `(|AP + BQ + CR|)/(|vec(C)S|)=`

In DeltaABC,L,M,N are points on BC,CA,AB respectively, dividing them in the ratio 1:2,2:3,3:5, if the point K divides AB in the ratio 5:3 , then (|bar(AL)+bar(BM)+bar(CN)|)/(|bar(CK)|)=

The points D,E,F divide BC,CA and AB of the triangle ABC in the ratio 1:4,3:2 and 3:7 respectively and the point divides AB in the ratio 1:3, then (AD+bar(BE)+bar(CF)):CK is equal to

In triangleABC, if the points P, Q, R divides the sides BC, CA, AB in the ratio 1:4, 3:2, 3:7 respectively and the point S divides side AB in the ratio 1:3, then (overline(AP)+overline(BQ)+overline(CR)):(overline(CS)) =

ABCD is a square. P, Q and Rare the points on AB, BC and CD respectively, such that AP = BQ = CR. Prove that: PB = QC

ABCD is a square. P, Q and Rare the points on AB, BC and CD respectively, such that AP = BQ = CR. Prove that: PQ = QR

If the point A, B, C, D are collinear asnd C, D divide AB in the ratios 2:3, -2:3 respectively, then the ratio in which AS divides CD is