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In a Coolidge tube, the potential differ...

In a Coolidge tube, the potential difference used to accelerate the electrons is increased from `12.4 kV` to `24.8 kV`. As a result, the difference between the wavelengths of `K_(alpha)`-line and minimum wavelength becomes thrice. The wavelength of the `K_(alpha)` line is `0.25xxKA^(@)`. Find the value of `K`. `(hc)/(e)=(12.4 KVA^(@))`

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