Define ` vec ax vec b` and prove that `| vec ax vec b|=( vec adot vec btantheta,` where `theta` is the angle between ` vec a` and ` vec b` .

Similar Questions

Explore conceptually related problems

prove that | vec axx vec b|=( vec adot vec b)t a ntheta,\ w h e r e\ theta is the angle between vec a\ a n d\ vec bdot

prove that | vec axx vec b|=( vec adot vec b)t a ntheta, w h e r e theta is the angle between vec a a n d vec bdot

Define vec axx vec b and prove that | vec axx vec b|=( vec a. vec btantheta, where theta is the angle between vec a and vec b ) .

Define vec a xxvec b and prove that |vec axvec b|=(vec a*vec b tan theta, where theta is the angle between vec a and vec b

Prove that |vec(a) xx vec(b)|=(vec(a)*vec(b)) tan theta," where " theta is the angle between vec(a) and vec(b) .

Prove that abs(vec(a) times vec(b))=(vec(a)*vec(b))tantheta , where theta is the angle between vec(a) and vec(b) .

If | vec a|+| vec b|=| vec c| and vec a+ vec b= vec c , then find the angle between vec a and vec bdot

If vec a\ a n d\ vec b are two vectors such that | vec axx vec b|=3\ a n d\ vec adot vec b=1, find the angle between vec a\ a n d\ vec b .