Calculate the energy required for the process.
`He_(g)^(+)rarrHe_(g)^(2+)=e^(-)`
The ionization energy for the H atom in its ground state is -13.6eV `atom^(-)`

Explanation

The ionization energy for the H atom in Its ground state`=13.6eV "atom"^(1)`
Ionization energy`=13.6z^(2)/(n^(2)eV)`
z=atomic number
n=principal quantum number or shell number
For He,n=1,z=2
`I.E.=(-13.6xx2^(2))/(1^(2))eV`
I.E. of`He^(+)` to `He^(2+)`=-54.4eV