An ion with mass number 37 possesses unit negative charge.If the ion contains 11.1% more neutrons than electrons.Find the symbol of the ion.

Explanation

Let the number of electrons in an ion=x
`therefore `Number of neutrons `=n=x+(11.1)/(100)eV`
`=1.111x`
(As the number of neutrons are 11.1% more than the number of electrons)
In the neutral of atom,number of electron.
`e^(-)=x-1`(As the icon carries-1 charge)
Similarly number of protons=P=x-1
Number of protons + number or neutrons=mass number =37
`:.(x-1)+1.111x=37`
2.111x=38
2.111x=38
`x=(38)/(2.111)=18.009=18`
`therefore`Number of protons =atomic number-1
=18-1=17
`therefore`the Number symbol of the icon`=underset(37)overset(17)( Cl)^(-)`