Energy if an electron in hydrogen atom in ground state is -13.6 eV. What is the energy of the electron in the third excited state?

Explanation

`E_1=-13.6eV`
`E_3=(-13.6)/(n^(2))` where n=3
`E_3=(-13.6)/(9)=1.511eV`
Energy of the electron iin the third excited state=1.511 eV.