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Calculate the molar conductance of 0.025...

Calculate the molar conductance of 0.025 M aqueous solution of calcium chloride at `25^@C` . The specific conductance of calcium chloride is `12.04 xx 10^(-2) Sm^(-1)`.

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Molar conductance = `Lambda_m = ((Sm^(-1)) xx 10^(-3))/(M) mol^(-1) m^3`
`= ((12.04 xx 10^(-2) Sm^(-1)) xx 10^(-3))/(0.025) mol^(-1) m^(3) = 481.10^(-2) Sm^(2) mol^(1)` .
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