If a current of 0.5 ampere flows through a metallic wire for 2-hours, then how many electrons would flow through the wire?

Explanation

`Q("coulomb") = 1("ampere") xx t("sec")`
`= 0.5 "ampere" xx 2 xx 60 xx 60 = 3600 C`
A flow of 1F, i.e., 96500 C is equivalent to the flow of 1 mole of electrons i.e., `6.023 xx 10^23` electrons
3600 C is equivalent to flow electrons = `(6.02 xx 10^(23))/(96500) xx 3600 = 2.246 xx 10^(22)` electrons.