How much copper is deposited on the cathode of an electrolytic cell if a current of 5 ampere is passed through a solution of copper sulphate for 45 minutes? [Molar mass of `Cu = 63.5 g mol^(-1), 1F = 96,500 Cmol^(-1)]`

Explanation

`Cu^(2-)(aq) + 2e^(-) to Cu(s)`
`m = Z xx I xx t`
`(63.5)/(2 xx 96500) xx 5 amp. xx 45 xx 60 = (857250)/(193000) = 4.44 g`.