Find the critical velocity for air flowing through a tube of 2cm diammeter .For air `rho=1.3xx10^(-3)gcm^(-3) and eta=181xx10^(-6)` poise

Water is flowing therough a tube of diameter 1 cm at 8 cm/s. Taking eta=10^(-2) poise the flow of liquid and Reynold's number are

Water is flowing therough a tube of diameter 1 cm at 8 cm/s. Taking eta=10^(-2) poise the flow of liquid and Reynold's number are

At STP, density of air is 1.3xx10^(-3)g*cm^(-3) . Vapour density of air is-

Determine the radius of a drop of water failling though air , if it covers 4.1 cm in 4 seconds with a unifrom velocity Assume density of air is0.001293 g cm^(-3) and eta for air 1.8xx10^(-4) poise.

What is the radius of a small oil drop while falling through air acquires a terminal velocity of Imm/s. The density of oil and air are 0.91g//cm^(3) and 1.3g//"lt" respectively and eta=1.8xx10^(-4) poisefor air

Compute the terminal velocity of rain drop of radius 0.3 mm take coefficient of viscosity of air= 1.83xx10^(-5) poise and density of air 1.3 kg m^(-3) Density of water= 10^3 kg m^(-3) and g =9.8m s^(-2)

What will be th approximate terminal velocity of a rain drop of diameter 1.8xx10^(-3)m . When density of rain water ~~10^(3) kgm^(-3) and the co-efficient of viscosity of air ~~1.8xx10^(-5) Nsm^(-2) ? (Neglect buoyacy of air)

What will be the approximate terminal velocity of a rain drop of diamteter 1.8xx 10^(-3)m, when density of rain water ~~10^(3)kgm^(-3) and the co-efficient of viscosity of air ~~1.8xx10^(-5)Nsm^(-2) ? (Neglect buoyancy of air. )