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Find the equation of the tangent and nor...

Find the equation of the tangent and normal to the Lissajous curve given by `x=2cos 3t and y=3 sin 2t, t in RR`.

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The correct Answer is:
That is `x sin 3t-y cos 2t =2sin 3t cos 3t-3 sin 2t cos 2t =sin 6t -(3)/(2) sin 4t`
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FULL MARKS-APPLICATIONS OF DIFFERENTIAL CALCULUS -ADDITIONAL QUESTIONS SOLVED
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