If the sides of a DeltaABC are a = 4, b ...

If the sides of a `Delta`ABC are a = 4, b = 6 and c = 8, show that 4 cos B + 3 cos C = 2.

Verified by Experts

The correct Answer is:

2

TRIGONOMETRY
FULL MARKS|Exercise Exercise 3.11|2 Videos
TRIGONOMETRY
FULL MARKS|Exercise Exercise 3.12|20 Videos
TRIGONOMETRY
FULL MARKS|Exercise Exercise 3.9|11 Videos
SOLVED PAPER 10
FULL MARKS|Exercise PART-IV|8 Videos
TWO DIMENSIONAL ANALYTICAL GEOMETRY
FULL MARKS|Exercise Additional Questions Solved|19 Videos

Similar Questions

Explore conceptually related problems

If the sides of Delta ABC are a = 4, b = 6 , c = 8 , then show that 4 cos B + 3 cos C = 2.

In Delta ABC if a to 2C and b to 3C , then cos B tends to

In a triangle ABC , a =2,b=3 and sin A = (2)/(3) then cos C=

In a Delta ABC, angleA = 60^(@), prove that b + c = 2a cos ((B - C)/(2)) .

Show that suma^3cos(B−C) =3abc

If Delta ABC is right triangle and if angleA = (pi)/(2) , then prove that cos B - cos C = -1 + 2 sqrt(2) cos"" (B)/(2) sin"" (C )/(2) .

In a Delta ABC , If tan A/2, tan B/2, tan C/2 are in A.P. then cos A. cos B, cos C are in

Solve the triangle ABC if a=5 , b=4 and angle A =60^(@ , then side c is

If A , Ba n dC are the angels of a triangle, show that |-1+cos B cos C+cos B cos B cos C+cos A-1+cos A cos A-1+cos B-1+cos A-1|=0