For the reaction `4NH_(3) + 5O_(2) to 4NO + 6H_(2) O`, if the rate of disappearance of `NH_(3)` is `3.6 xx 10^(-3)` mol `L^(-1) s^(-1)`, what is the rate of formation of `H_(2) O`

For the reaction N_(2)O_(5) rarr 2NO_(2) + (1)/(2) O_(2) , the rate of disappearance of N_(2)O_(5) is 6.25 xx 10^(-3) "mol L"^(-1) s^(-1) . The rate of formation of NO_(2) and O_(2) will be respectively.

For the reaction N_(2)O_(5) rarr 2NO_(2) + (1)/(2) O_(2) , the rate of disappearance of N_(2)O_(5) is 6.25 xx 10^(-3) "mol L"^(-1) s^(-1) . The rate of formation of NO_(2) and O_(2) will be respectively.

For the reaction N_(2)O_(5)(g) to 2NO_(2)(g)+(1)/(2)O_(2)(g) the rate of disappearance of N_(2)O_(5) is 6.25xx10^(-3)"mol"L^(-1)s^(-1) . The rate of formation of NO_(2) and O_(2) will be respectively

Ammonia and oxygen react at high temperature as : 4 NH _(3)(g) to 4NO (g) + 6 H _(2) O (g) in an experiment, the rate of formation of NO is 3.6 xx 10 ^(-3) mol L ^(-1) sec ^(-1). Calculate the rate on formation of H _(2)O.

For the reaction 4NH_(3) + 5O_(2) to 4NO + 6H_(2)O , the rate of reaction with respect to NH_(3) is 2 xx 10^(-3) Ms^(-1) . Then the rate of the reaction with respect to oxygen in Ms^(-1)