An aqueous solution of ` (PdCl_2) 4NH_3` when treated with excess of ` AgNO_3` precipitated 2 moles of ` AgCl` .Predict the secondary valency of the compound.

Assertion : Aqueous solution of the compound CoCl_(3) * 4NH_(3) when treated with excess of AgNO_3 , 1 mole of AgCl is precipitated . Reason : The compound CoCl_(3) * 4NH_(3) has six primary valencies and one secondary valency .

Assertion : Aqueous solution of the compound CoCl_(3) * 4NH_(3) when treated with excess of AgNO_3 , 1 mole of AgCl is precipitated . Reason : The compound CoCl_(3) * 4NH_(3) has six primary valencies and one secondary valency .

Assertion : Aqueous solution of the compound CoCl_3. 4 NH_3 when treated with excess of AgNO_3 1 mole of AgCl is precipitated. Reason : The compound CoCl_3. 4NH_3 has six primary valencies and one secondary valency.

When one mole of CoCl_(3).5NH_(3) was treated with excess of silver nitrate solution, 2 mol of AgCl was precipitated. The formula of the compound is:

One mole of aqueous solution of the complex CoCl_(3)5H_(2)O when treated with excess of aqueous AgNO_(3) solution gave one mole of white pptof AgCl. What is the complex?

1 mole of complex CoCl_(3).6NH_3 on reaction with AgNO_3 gives 3 moles of AgCl precipitate. The secondary valency of complex is-

When 1 mol CrCl_3 .6H_2O is treated with excess of AgNO_3 , 3 3 mol of AgCl are obtained. The formula of the complex is:

When 0.1 mol CoCl_3(NH_3)_5 is treated with excess of AgNO_3 , 0.2 mol of AgCl are obtained. The conductivity of solution will correspond to

When 0.1 mol CoCl_(3)(NH_(3))_(5) is treated with excess of AgNO_(3) , 0.2 mole of AgCl are obtained. The conductivity of solution will correspond to