An excited hydrogen atom emits a photon of wavelength `lambda` in returning to the ground state. If 'R' is the Rydberg's constant, then the quantum number 'n' of the excited state is:

An excited hydrogen atom emits a photon of wavelength t while returning to the ground state. If R is the Rydberg.s constant, then the quantum number n of the excited state is

An excited He^(+) ion emits photon of wavelength lambda in returning to ground state from n^(th) orbit. If R is Rydberg's constant then :

An excited He^(+) ion emits photon of wavelength lambda in returning to ground state from n^(th) orbit. If R is Rydberg's constant then :

An excited He^(+) ion emits photon of wavelength lamda in returning to ground state from n^(th) orbit. If ʻR’ is Rydberg constant, then

Hydrogen atom from excited state comes to the ground state by emitting a photon of wavelength lambda . If R is the Rydberg constant, then the principal quatum number n of the excited state is

Hydrogen atom from excited state comes to the ground state by emitting a photon of wavelength lambda . If R is the Rydberg constant, then the principal quatum number n of the excited state is

Hydrogen atom from excited state comes to the ground state by emitting a photon of wavelength lamda . If R is the Rydberg constant the principal quantum a number n of the excited state is

An excited state of H atom emits a photon of wavelength lamda and returns in the ground state. The principal quantum number of excited state is given by: