`inte^x(1-cotx+cot^2x)dx=` `e^xcotx+C` (b) ` e^xcotx+C` (c) `e^x\ cos e c\ x+C` (d) ` e^x\ cos e c\ x+C`

int e^(x)(1-cot x+cot^(2)x)dx=e^(x)cot x+C (b) e^(x)cot x+C(c)e^(x)cos ecx+C(d)e^(x)cos ecx+C

int e^(-x) cosec x(1+ cot x) dx is equal to a) e^(-x) cosec x + C b) -e^(-x) cosec x + C c) - e^(-x) ( cosec x + cot x ) + C d) - e^(-x) ( cosec x - tan x ) + C

int e^x sec x(1+tan x) d x equals A) e ^x cos x+C B) e^x sec x+C C) e^x sin x+C D) e^x tan x+C

int e^x ((1-sinx)/(1-cosx)) dx= (A) e^xtan(x/2)+C (B) e^xcot(x/2)+C (C) -1/2 e^xtan(x/2)+C (D) -1/2 e^xcot(x/2)+C

int x^2 . e^(x^3) dx = (a) e^(x^3) + C (b) e^(x^2) + C (c) 1/3 e^(x^3) + C (d) 1/3 e^(x^2) + C

int(x-1)\ e^(-x)\ dx is equal to x e^x+C (b) x e^x+C (c) -x e^(-x)+C (d) x e^(-x)+C

inte^(-x)(1-tanx)secxdx is equal to a) e^(-x)secx+c b) e^(-x)tanx+c c) -e^(-x)tanx+c d) -e^(-x)secx+c

int(e^x(1+x))/(cos^2(x e^x))\ dx= (a) 2(log)_ecos(x e^x)+C (b) sec(x e^x)+C (c) tan(x e^x)+C (d) tan(x+e^x)+C

Evaluate: inte^x\ (cotx-cos e c^2x)\ dx