Home
Class 12
CHEMISTRY
The conductivity of 0.00241 M acetic aci...

The conductivity of `0.00241 M` acetic acid is `7.896xx10^(-5)Scm^(-1)`. Calculate its molar conductivity. If `wedge_(m)^(@)` for acetic acid is `390.5Scm^(2)mol^(-1)`, what is its dissociation constant ?

Promotional Banner

Similar Questions

Explore conceptually related problems

Conductivity of 0.00241M acetic acid solution is 7.896xx10^(-5)S.cm^(-1) . Calculate its molar conductivity. If Lambda_(m)^(@) for acetic acid is 390.5S.cm^(2).mol^(-1) , what is its dissociation constant ?

Conductivity of 0.00241M acetic acid is 7.896 xx 10^(-5) S cm^(-1) . Calculate its molar condcutivity. If Lambda_(m)^(@) acetic acid is 390.5 S cm^(2) "mol"^(-1) , what is its dissociation constant?

Conductivity of 0.00241 M acetic acid is 7.896 x 10^(-5) S cm^(-1). Calculate its molar conductivity. If A°_m for acetic acid is 390.5 S cm^2 mol^(-1) , what is its dissociation constant?

Conductivity of 0.00241 M acetic acid is 7.896 xx 10^(-4) S cm^(-1) . Calculate its moar conductivity and if ^^_(m)^(@) for acetic is 390.5 S cm^(2) mo^(-1) , what is its dissociation constant ?

Conductivity of 0.003 M sulphuric acid is 6.896xx10^(-5)"S "cm^(-1) . Calculate its molar conductivity and if wedge^(@)m for sulphuric acid is 490.5 Scm^(2)mol^(-1) , what is its dissociation constant?